How much of a 0.5% solution is needed to provide 25 mg of active ingredient?

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Multiple Choice

How much of a 0.5% solution is needed to provide 25 mg of active ingredient?

Explanation:
To determine how much of a 0.5% solution is needed to provide 25 mg of active ingredient, it’s essential to first understand what a 0.5% solution means. A 0.5% solution contains 0.5 grams of the active ingredient in 100 milliliters of solution. Since we want to find out how many milliliters of this solution provides 25 mg of the active ingredient, we can start by converting milligrams to grams. There are 1000 mg in a gram, so 25 mg is equal to 0.025 grams. Using the concentration of the solution (0.5 grams per 100 mL), we can set up a proportion to find the volume needed: 0.5 grams = 100 mL 0.025 grams = x mL By cross-multiplying, we find: 0.5 grams * x mL = 0.025 grams * 100 mL Solving for x gives us: x = (0.025 grams * 100 mL) / 0.5 grams x = 2.5 mL This calculation indicates that to get 25 mg (or 0.025

To determine how much of a 0.5% solution is needed to provide 25 mg of active ingredient, it’s essential to first understand what a 0.5% solution means. A 0.5% solution contains 0.5 grams of the active ingredient in 100 milliliters of solution.

Since we want to find out how many milliliters of this solution provides 25 mg of the active ingredient, we can start by converting milligrams to grams. There are 1000 mg in a gram, so 25 mg is equal to 0.025 grams.

Using the concentration of the solution (0.5 grams per 100 mL), we can set up a proportion to find the volume needed:

0.5 grams = 100 mL

0.025 grams = x mL

By cross-multiplying, we find:

0.5 grams * x mL = 0.025 grams * 100 mL

Solving for x gives us:

x = (0.025 grams * 100 mL) / 0.5 grams

x = 2.5 mL

This calculation indicates that to get 25 mg (or 0.025

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